Revising is the third stage of the writing process. You read through your message and decide whether is achieves your purpose

Bakery has bought 250 pounds of muffin dough. they want to make waffles or muffins in half-dozen packs out of it. half a dozen of muffins requires 1 lb of dough and a pack of waffles uses 3/4 lb of dough. it take bakers 6 minutes to make a half-dozen of waffles and 3 minutes to make a half-dozen of muffins. their profit will be $1.50 on each pack of waffles and $2.00 on each pack of muffins. how many of each should they make to maximize profit, if they have just 20 hours to do everything?

Dr. sperry, a biologist, is using excel to track growth rates of different populations of bacteria. she has a very complex formula in one cell. it begins with “round”. dr. sperry would like to see exactly how excel’s calculation reached the final rounded value that she sees in the cell. what could dr. sperry do to best understand how the calculation was made? try different formulas on her own until she reaches the value shown in excel click on the evaluate formula button in the formulas tab and then click “step in” select the cell and then look at the formula in the formula field of the ribbon remove “round” from the formula in order to see the actual value before rounding

David consumes two things: gasoline (g) and bread (b). david's utility function is u(g, b) = 10g^0.25 b^0.75. use the lagrange technique to solve for david's optimal choices of gasoline and bread as a function of the price of gasoline, p_g, the price of bread, p_b, and his income m. with recent decrease in the price of gasoline (maybe due to external shock such as shale gas production) does david increase his consumption of gasoline? for david, how does partial differential g/partial differential p_g depend on his income m? that is, how does david's change in gasoline consumption due to an increase in the price of gasoline depend on his income level? to answer these questions, find the cross-partial derivative, |partial differential^2 g/partial differential m partial differential p_g.