Aphoton with momentum p = 1.02 mev/c, where c is
the velocity of light, is scattered by a stationary free electron,
changing in the process its momentum to the value p' = 110.255 mev/c.
at what angle is the photon scattered?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

No because scientist are still changing there mines today so they are not correct to this day

The best description is: . nobody has any idea what q is.