Both parents are heterozygous for the huntington's allele. what is the chance that their child will not have huntington's disease

25% or 1/4

Explanation:

The cross in this question involves a gene coding for the possession or not of Huntington's disease in humans. The dominant allele is denoted by (H) while the recessive allele is denoted by (h). The possession of the dominant allele by an individual means the possession of the Huntington's disease.

In a cross between two heterozygous parents i.e. combination of both dominant and recessive alleles (Hh). Four possible offsprings will be produced with genotypes HH, Hh, Hh and hh.

The genotypes HH, Hh and Hh will phenotypically possess the Huntington's disease while the hh genotype will not possess the Huntington's disease. Hence, the chance of having a child without the disease is 1/4 or 25%.

oak trees? ? what was listed

small, big, or no change could occur in the phenotype. it could cause something as simple as a cats ears to curl backwards or something as frighting as death. it could also occur in the protien-coding area and have an effect on that but no effect on the amino acids. what has to occur is a changing in the hox gene or the control gene.