Suppose that you performed a version of the hershey and chase experiment, this time using 32p-labeled viruses that insert their double-stranded dna into the dna of the cells that they infect. the viral dna is then treated as part of the cell's own dna and is replicated during dna replication and passed onto daughter cells when the cell divides. you infect a population of cells with the 32p-labeled viruses, and then let the infected cells go through two generations of cell divisions. if you then examine the cells, you should find 32p-labeled dna in of the cells.

1/2 of the cells.

Explanation:

DNA replication is a semiconservative process which means that one strand of each of the two DNA double helices formed after one round of DNA replication is the parental strand and the other one is the newly formed strand.  

Given that a population of the cells was infected with 32P-labeled viruses which would insert its DNA into the host cell's DNA, after one generation of cell division, the 32-P labeled DNA would be present in one strand of all the DNA molecules present in all the cells.  

After the second generation of cell division, the 32-P labeled parental strand would be present in 1/2 of the total cells while the rest half of the cells would have only the normal DNA.  

there’s no image attached but i can if you want: )