Arocket is launched from the top of a 7ft platform. its initial velocity is 112 ft per sec. it is launched at an angle of 60° with respect to the ground. (a) find the rectangular equation that models its path. what type of path does the rocket follow

Parbolic path.

Step-by-step explanation:

This is bidimensional motion, so the equation that relates the vertical and horizontal position is:

Here, v₀, θ y g are constants, then we can rewrite (1) as:

where:

Therefore the rectangular equation will be:

This type of path is a parabolic motion.

I hope it helps you!

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