Advanced Placement (AP), 13.01.2021 14:00 nbayoungboy589
The radius of a cone is increasing at a constant rate of 2 feet per second. The volume remains a constant 373 cubic feet. At the instant when the height of the cone is 55 feet, what is the rate of change of the height? The volume of a cone can be found with the equation V=\frac{1}{3}\pi r^2 h. V=
3
1
Ďr
2
h. Round your answer to three decimal places.
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The radius of a cone is increasing at a constant rate of 2 feet per second. The volume remains a con...
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