A1000-kg car is slowly picking up speed as it goes around a horizontal unbanked curve whose radius is 100 m. the coefficient of static friction between the tires and the road is 0.35. at what speed will the car begin to skid sideways?

18.71 m/s

Explanation:

Solving the question, we must know that in an horizontal curve,frictional force is equal to centripetal force, that is,

Horizontally, frictional force= centripetal force

U×m×g= mv^2/r(1)

U= coefficient of static friction, m= mass of the car, g= gravitational acceleration.

grU= V^2 (2)

From the equation, we have the following information information; U= 0.35, g= 10 metre per seconds, radius,r= 100 m, mass of the car= 1000 kg

Slotting in the parameters into equation (2) above.

10 m/s × 100 m × 0.35= v^2

350=v^2

v= 18.71 m/s

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