Two cities are 45 miles apart. two trains, with speeds of 70 mph and 60 mph, leave the two cities at the same time so that one is catching up to the other. how long after the trains leave will the distance between them be 10 miles? a how many solutions does the problem have?

The correct answer is  27' (minutes). The problem actually has only one solution.

Explanation:

We have to part from the basic speed-distance-time formula:

s=d/t

The time until they are distanced 10 miles is the same since the two trains leave at the same moment. We will call that time: t We will call the first train: A d1 is the distance train A traveled until it is distanced 10 miles from train B

70=d1/t

70t = d1

We will call the second train: B d2 is the distance train B traveled until it is distanced 10 miles from train A

60=d2/t

60t = d2

So, the distance between A and B when the trains leave is: 45 miles

d1 + d2 + 10 = 45

70t + 60t = 35

130t = 35

t=27’

The problem actually has only one solution.

Hamlet's fourth soliloquy is probably his most famous one - "to be or not to be."it is rather different from his previous soliloquies because now he is contemplating something that didn't come up before - suicide. he is thinking whether it is worth it to fight to find his father's murderer when in the end all of them are going to die, so why not die sooner than later. he is contemplating if he should go on fighting or just kill himself and end it all, which is why this soliloquy in particular is rather depressing, hesitant, and gives a deeper insight into hamlet's madness.

Ithink it is b  employees