calculate the standard enthalpy of formation of liquid methanol, ch3oh(l), using the following information: c(graph) + o2 → co2(g) δh° = -393.5 kj/mol h2(g) + (1/2)o2 → h2o(l) δh° = -285.8 kj/mol ch3oh(l) + (3/2)o2(g) → co2(g) + 2h2o(l) δh° = -726.4 kj/mol

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i havent taken the psat, but i have the sat, make sure to bring some snacks, because youre in there forever, 2 sharp number two pencils, an sat approved calculator, and maybe a jacket.   your phone and any books will be taken up, so don't try to bring them(but they will be given back at the end of the testing).   good luck!   i hope you do well!

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this ni gga

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what the heck this is weird that they would do that

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every thing is fine

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