a metal sphere with radius r1 has a charge q1. take the electric potential to be zero at an infinite distance from the sphere.

Part A: E = E. Q; / R;? Volt / meter Part B: V = Eo Q1 / R, Volt Explanation: Since, the charge distributed on the sphere is Q, the radius of the sphere is R 1 The electric potential at infinity is 0

Part A The space around a charge in which its influence is felt is known in the electric field. The strength at any point inside the electric field is defined by the force experienced by a unit positive charge placed at that point. If a unit positive charge is placed at the surface it experiences a force according to the Coulomb law is given by% 3D E. Q1 / R ;? Then the electric field at that point is E = F / 1 E = E E. Q / R ;? Volt / meter

Part B The electric potential at a point is defined as the amount of work done in moving a unit positive charge from infinity to that point against electric forces. Thus, the electric potential at the surface of the sphere of radius R, and charge distribution Q, is given by the relation V = E. Q1 / R, Volt% 3D

The eocs or end of course exams i believe