If X > 0, what is one possible solution to this equation x^3 (x^2-5) = -4x

distribute x³ :

move variable to the left-hand side:

factorize out x :

write -5x as difference:

factorize x² from the equation:

factorize -4 from the equation:

factorize (x²-1) from the equation:

products:

1) x = 0

*ignore this as your question wants x>0

2) x²-1 = 0

x² = 1

x = √1

x=1

3) x²-4 = 0

x² = 4

x = √4

x=2

thus, x=1, x=2