Physics, 22.07.2019 11:30 dareaalcaam111

What is the acceleration of a block on a ramp inclined 35o to the horizontal if µk = 0.4?

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We can solve the problem by applying Newton's second law, which states that the resultant of the forces acting on an object is equal to the product between its mass and its acceleration:
$\sum F = ma$

We should consider two different directions: the direction perpendicular to the inclined plane and the direction parallel to it. Let's write the equations of the forces along the two directions, decomposing the weight of the object (mg):

$mg \sin \theta - \mu_K N = ma$ (parallel direction) (1)
$mg \cos \theta - N =0$ (perpendicular direction) (2)
where
$\theta=35^{\circ}$ is the angle of the inclined plane, N is the normal reaction of the plane, $\mu_K N$ is the frictional force, with $\mu_K=0.4$ being the coefficient of friction.

From eq.(2), we find
$N=mg \cos \theta$
and if we substitute into eq.(1), we can find the acceleration of the block:
$mg \sin \theta - \mu_k mg \cos \theta = ma$
from which
$a=g(\sin \theta - \mu_K \cos \theta)=(9.81 m/s^2)(\sin 35^{\circ} - 0.4 \cos 35^{\circ})=2.41 m/s^2$

Answer from: Quest

the displacement produced by the body.

the amount of force subjected to the body.

the angle between the direction of force and displacement

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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