At what distance above the surface of the earth is the acceleration due to the earth's gravity 0.995 m/s2 if the acceleration due to gravity at the surface has magnitude 9.80 m/s2?

The distance above the surface of the earth is .

Explanation:

Given that,

Acceleration due to the gravity g'= 0.995 m/s² (at height )

Acceleration due to the gravity g= 9.80 m/s² (at surface )

We know that,

The formula of gravity at height

Where, h = height

r= radius of the earth

We substitute the value into the formula

Hence, The distance above the surface of the earth is .

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

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