Supernova explosions are known to release a large amount of energy. a detector for which type of electromagnetic radiation is most suitable to study a supernova explosion? gamma ray infrared radio wave visible light

Gamma ray  

Explanation:

The most energetic radiation is the Gamma ray. It has largest frequency (>10¹⁹ Hz) smallest wavelength and thus, highest energy. As compared to Gamma ray, infra red, visible and radio wave have low energy.  When a heavy mass stars undergoes supernova, it releases a large amount of energy in a small interval of time. Thus, supernovae explosions can be detected by using Gamma rays.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

okay i have so many questions. but the big one here is: um wt..f is this mess? ?