An arrow is aimed horizontally, directly at the center of a target 20 m away. the arrow hits 0.050 m below the center of the target. neglecting air resistance, what was the initial speed of the arrow?

200 m/s

Explanation:

h = 0.05 m, x = 20 m, uy = 0, g = 10 m/s^2

Let the speed in horizontal direction is u and the time taken is t.

h = uy t + 1/2 gt^2

0.05 = 1/2 x 10 x t^2

t = 0.1 s

Horizontal distance = horizontal speed x time

x = u x t

20 = u x 0.1

u = 200 m/s

answer: what are you talking about?

explanation: