Can anyone me with any parts in question number 1: parallel circuit?

Question #1:

a).  The sketch is attached to this answer.

b).  The equivalent resistance of 30Ω and 50Ω in parallel is

1 / (1/30 + 1/50)  =  18.75 Ω

c).   I = V/R = (100/30) = (3 and 1/3) Amperes

d).  Follow the wires, and you see that the 50Ω resistor is
connected directly to the battery, and so is the voltmeter.
So the voltage across the 50Ω resistor, and the reading 
on the voltmeter, is 100 volts.

e).  I = V/R
Through the 30Ω resistor:  I = 3-1/3 A
Through the 50Ω resistor:  I = 2 A

f).  In the parallel circuit, both resistors are connected
directly to the battery.  So neither resistor even knows
that the other one is there.  Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.

Kinetic energy = 1/2mv^2. since the mass is constant we can form a ratio of it's kinetic energy at 60 divided by that at 30 to see ke(60)/ke(30) = +(60^2)/30^2). this may be said to 300% increase.