What is the electric force acting between two charges of 0.0072 c and -0.0060 c that are 0.0040 m apart? a. 9.7 x10^7 n b. -9.7 x10^7 n c. 2.4 x10^10 n d. -2.4 x10^10 n

F = -2.4 * 10¹⁰ N

Explanation:
To get the electric force between two charges, we would use Coulomb's law which states that:
F = 

where:
F is the force between the two charges
k is Coulomb's constant = 9 * 10⁹ Nm²/C²
q1 is the first charge = 0.0072 C
q2 is the second charge = -0.006 C
d is the distance between the two charges = 0.004 m

Substitute with the givens in the above formula to get the force between the two charges as follows:
F = 

F = -2.4 * 10¹⁰ N

Hope this helps :)