Assume that the x components of the blocks' momenta at a certain moment are p1x and p2x. find the x component of the velocity of the center of mass (vcm)x at that moment. express your answer in terms of m1, m2, p1x, and p2x.

Explanation:

The amount of movement is the product of the mass of a body because of its speed, the speed is that of the center of mass; The equation is:

    p = mv

Where v is the velocity of the center of mass of the body, what we have to do is clear the velocity

      V = p / m

  It is our case for each body and as the amount of movement is a vector we must write it for each axis

   V1x = p1x / m1

   V2x = p2x / m2

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.