Aspring scale hung from the ceiling stretches by 5.6 cm when a 2.0 kg mass is hung from it. the 2.0 kg mass is removed and replaced with a 2.7 kg mass. what is the stretch of the spring

When the mass of 2.0 kg is attached to the spring, the force applied to the spring is the weight of the mass, so

This force stretches the spring by , so we can use Hook's law to find the spring constant:


Then the mass of 2.0 kg is removed and replaced with another mass m2=2.7 kg. The force produced by this mass is equal to its weight:

And so, we can use again Hook's law to calculate the new stretch of the spring:

Edit the post so i can see the letters for each answer, and increase the points required so i'd be able to answer it.

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