Arocket of total mass 3180 kg is traveling in outer space with a velocity of 115 m/s toward the sun. it wishes to alter its course by 30.0°, and can do this by firing its rockets briefly in a direction perpendicular to its original motion. if the rocket gases are expelled at a speed of 1750 m/s, how much mass must be expelled?

Let Vx = 115m/s 

in order for the angle to be 30 degrees 

tan 30 = Vy/115

Vy = 66.40 m/s 

Using conservation of momentum:

m(1750) = (3180 - m) 66.40 

1750m = 211152 – 66.40m 

1750 m + 664.40 = 211152

1816.40 m = 211152

m = 211152 / 1816.40

m = 116.25 kg would be the answer

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2