How many air molecules are in a 14.0×12.0×10.0 ft room? assume atmospheric pressure of 1.00 atm, a room temperature of 20.0 ∘c, and ideal behavior. volume conversion: there are 28.2 liters in one cubic foot?

There are 1.19.10²⁷ air molecules in the room

In general, the gas equation can be written

where

P = pressure, atm, N / m²

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K (P = atm, v = liter), or 8.314 J / mol K (P = Pa or N / m2, v = m³)

T = temperature, Kelvin

n = N / No

n = mole

No = Avogadro number (6.02.10²³)

n = m / m

m = mass

M = relative molecular mass

room volume: 14x12x10 = 1680 ft³

T = 20 °C = 20 +273 = 293 K

1 ft³ = 28.2 liters, then

1680 ft³ = 47376 liters

Which equation agrees with the ideal gas law  

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Which law relates to the ideal gas law  

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increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

the assestment will probley apele with cause and effect