Particle q₁ has a charge of 2.7 μc and a velocity of 773 m/s. if it experiences a magnetic force of 5.75 × 10⁻³ n, what is the strength of the magnetic field?
a. 0.36 t
b. 1.6 t
c. 2.8 t

in the same magnetic field, particle q₂ has a charge of 42.0 μc and a velocity of 1.21 × 10³ m/s. what is the magnitude of the magnetic force exerted on particle 2?
a. 0.042 n
b. 0.12 n
c. 0.14 n

The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to

where is the angle between the directions of v and B.

1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is . In this case, v and B are perpendicular, so , therefore we have:


2) In this second case, the angle between v and B is . The charge is now , and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:

Special care would be an answer