If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the water?

Distance, d = 44.1 meters

Explanation:

It is given that, if a stone dropped into a well reaches the water's surface after 3.0 seconds, t = 3 s

We need to find the distance covered by the stone before hitting the water. Let distance covered is s. It can be calculated using second equation of motion as :

Here, u = 0 and a = g

s = 44.1 meters

So, the distance covered by the stone before hitting the water is 44.1 meters. Hence, this is the required solution.

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