The rope will snap if the tension in it exceeds 55.0 n. what is the maximum value of the force f which can be applied?

Missing part of the text:
"Two masses, m1 = 2.12 kg and m2 = 9.01 kg are on a horizontal frictionless surface and they are connected together with a rope as shown in the figure."
and missing figure (see attachment)

Solution:
We can write Newton's second law for the whole system m1-m2 and for m2 only (2 equations). Only one force (F) acts on the m1-m2 system, while if we consider m2 only we have two forces acting on it: F and T (tension), in the opposite direction. So, the two equations are


where a is the acceleration of the system.

From the first equation we get

and substituting it inside the second equation, we get

re-arranging, we get
 

Using , , and using the maximum value of T that is allowed not to break the rope (T=55 N), we can find the maximum allowed value for F:

50 meters per 5 seconds

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way