Arocket starts from rest and moves upward from the surface of the earth. for the first 10.0 s of its motion, the vertical acceleration of the rocket is given by ay=(2.70m/s3)t, where the +y-direction is upward. what is the speed of the rocket when it is 325 m above the surface of the earth?

Explanation:

The vertical acceleration of the rocket is given by :

Acceleration is given by,

..............(1)

Velocity is given by,

From above equation, we can find the value of t at x = 325 m

t = 8.97 s

Now put t = 8.97 s in equation (1) as :

v = 108.62 m/s

So, the speed of the rocket when it is 325 meters above the surface of earth is 108.62 m/s. Hence, this is the required solution.

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?

like poles repel so keep pushing north to north and repels funny to see this