How much heat is absorbed by a 39g iron skillet when its temperature rises from 15oc to 24oc?

To begin, your equation is Q=mc{triangle}T

Q is the end heat in Joules
m is the mass
c is the specific heat
and
{triangle} T is the change in temperature

Now that we have the equation down, we are trying to find the end heat.
Your specific heat, I suspect is 0.450 J/g{degrees}C because its the specific heat of iron. Making your equation you'll get:

Q=(39g)x(0.450 J/g{degrees}C)x(9{degrees}C)

Multiplying it all you'll get:

Q= 157.95J
or
157.95 Joules

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