An object undergoes acceleration of 2.3i^+3.6j^m/s2 over a 10-s interval. at the end of this time, its velocity is 33i^+15j^m/s. by how much did its speed change

12.99 m/s

Explanation:

Since the acceleration is constant, we can use the following formula for the velocity

        (1)

Where:



Since at t = 10 s,



the unknown variable in equation (1) is .

At t = 10 s, equation 1 becomes:

        (2)

By subtracting both sides of equation (2) by , we have



Now, we let

v(10) = speed of the object at t = 10
v(0) = speed of the object at t = 0

Recall that speed is the magnitude of the velocity and so



Hence, the change of speed after 10 s is given by 

Try c ? that’s what i got