Aperson pushes on the handle of a lawnmower with a force of 280. n. if the handle makes an angle of 40.0 degrees with the ground, calculate the coefficient of friction if the lawnmower weighs 350. n and is moving at a constant velocity.

µ= 0.405

Explanation:

Acceleration is 0 (constant V), so all the forces in the horizontal direction must add up to 0. Specifically those are these two:

Horizontal component of the force of (F1). It acts FORWARD.  

F1 = F*cosθ = 280cos40 N

Force of friction

F(fr) = µ*(total pressure force).

Two forces are creating the pressure force (Fp).

The other is the vertical component of F It's equal to

F*sinθ = 280sin40.

Then the friction force

F(fr) = µ*(mg + 280sin40)

Since

F1 = F(fr),

280cos40 = µ*(mg + 280sin40)

µ = 280cos40 / (mg + 280sin40)

µ= 0.405

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

it would be c. predictability