A3.0 kg block is acted upon by a horizontal force f(x) = 26.0 - 9.0x where the force is measured in newtons if x is measured in meters. the coefficient of kinetic friction between the block and the flat surface is 0.20. the block is initially at x = 0 m. what distance must the block travel if the net work done on the block by f(x) and friction combined is to be exactly zero?

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm