Aperson weighing 785 newtons on the surface
of earth would weigh 298 newtons on the
surface of mars. what is the magnitude of the
gravitational field strength on the surface of
mars?
(1) 2.63 n/kg (3) 6.09 n/kg
(2) 3.72 n/kg (4) 9.81 n/kg

                      Weight anywhere = (mass) x (gravity there)

The acceleration of gravity on Earth is 9.8 m/s² .
So on Earth . . .

                       785 N = (the person's mass) x (9.8 m/s²)

Divide each side by (9.8 m/s²):

                       The person's mass = (785N) / (9.8 m/s²)


On Mars, 
                 (his weight) = (his mass) x (acceleration of gravity on Mars)

              298 newtons  =  (785/9.8  kg) x (acceleration of G on Mars)

Divide each side by  (785/9.8 kg):

           Acceleration of gravity on Mars =

                      (298 newton) / (785/9.8 kg) =  3.72 N / kg .
  

We can infer that star y is closer but other factors must be considered including the heat of the star, the mass, and the brightness of the star. even though star x seems dimmer it may just be less bright or contain less heat.