Acar moving south speeds up from 10 m/s to 40 m/s in 15 seconds. what is the car’s acceleration? a. 2 m/s2 b.15 m/s2 c.30 m/s2 d.50 m/s2

Acceleration,

Explanation:

It is given that,

A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds.

It means,

Initial velocity of the car, u = 10 m/s

Final velocity of the car, v = 40 m/s

Time taken, t = 15 seconds

We have to find the acceleration of the car. Mathematically, acceleration of the car is given by taking difference in velocities divided by time taken i.e.

Hence, this is the required solution.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge