Abus and a car have an inelastic head-on collision. the bus has a mass of 1.5 × 103 kilograms and an initial velocity of 20 meters/second. the car has a mass of 9.5 × 102 kilograms and an initial velocity of -26 meters/second. what is their total momentum after the collision?

+5300 kg m/s

Explanation:

In any type of collision, the total momentum is conserved. Therefore, we can just calculate the total momentum before the collision, and the final momentum will be equal to the initial one.

The total momentum before the collision is:

where

is the mass of the bus

is the mass of the car

is the initial velocity of the bus

is the initial velocity of the car

Substituting the numbers, we find

And since the total momentum is conserved, this is also the final momentum after the collision.

p = 5300 kg-m/s

Explanation:

It is given that,

Mass of the bus,

Initial velocity of the bus,

Mass of the car,    

Initial velocity of the car,

Let p is their total momentum after the collision. It can be given by :

p = 5300 kg-m/s

So, their total momentum after the collision is 5300 kg-m/s. Hence, this is the required solution.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .