Why does the cyclist have less kinetic energy at position a than at position b?

Suppose that the cyclist begins his journey from the rest from the top of a wedge with a slope of a degree above the horizontal.
 At point A (where it starts its journey), the energy is:
 Ea = m * g * h
 In other words, energy is only potential.
 At point B (located at the bottom of the wedge), the energy is:
 Eb = (1/2) * (m) * (v ^ 2)
 In other words, the energy is only kinetic.
 For energy conservation we have:
 Ea = Eb
 That is, we have that all potential energy is transformed into kinetic energy.
 Which means that the cyclist has less kinetic energy at point A because that's where he has more potential energy.
 
 the cyclist has less kinetic energy at point A because that's where he has more potential energy.

Ithink the answer is c but then again i'm probably wrong