Astudent conducted an experiment to measure the acceleration due to gravity 'g' of a simple pendulum.
length of thread , l/m : 0.35
time for 20 oscillations, t/s : 24.1
length of thread, l/m : 0.65
time for 20 oscillations : 3.24
length of thread, l/m : 1.00
time for 20 oscillations : 4.01
lenght of thread, l/m : 1.45
time for 20 oscillations : 47.5
length of thread : 1.95
time for 20 oscillations : 56.3
given that the realtion between the period 't', the length of the pendulum 'l' and the acceleration due to gravity 'g' is t=2(pi)√(l/g), find the value of 'g'.

How do the measurements of charge at the different locations on the sphere compare to each other? the charge measurements are different at all locations on the sphere. the charge measurements are virtually not the same at all locations on the sphere except for the charge at the very top and at the very bottom that are equal. the charge measurements are virtually the same at all locations on the sphere except for the charge at the very top. at the top, the conductive sphere has a small disk that is made of different material. the charge measurements are the same at all locations on the sphere. what happens to the charge on the conductive sphere when it is connected to a source of charge such as the electrostatic voltage source? nothing will happen because no charge goes around the surface of the sphere. the charge on the conductive sphere spreads out over the surface of the sphere; being greater in some specific locations on the sphere. the charge on the conductive sphere spreads out uniformly over the surface of the sphere. the charge on the conductive sphere spreads out non-uniformly over the surface of the sphere.

What will a positive and a negative charge do if they are separated from each other?

Carbon is allowed to diffuse through a steel plate 15 mm thick. the concentrations of carbon at the two faces are 0.65 and 0.30 kg c/m^3 fe, which are maintained constant. if the preexponential and activation energy are 6.2 x 10-7 m2 /s and 80,000 j/mol, respectively, compute the temperature at which the diffusion flux is 1.43 x 10^-9 kg/m^2 -s.