Find the length of a pendulum that oscillates with a frequency of 0.15 hz. the acceleration due to gravity is 9.81 m/s 2 . answer in units of m.

Frequency of the pendulum F = 0.15Hz Acceleration due to gravity g = 9.81 m/s^2 Period of the pendulum is calculated by T = 2 x 3.14 x squareroot of (L / g), L being the length of the pendulam. We have an equation between T and F => T = 1 / F T = 1 / 0.15 => T = 20 / 3 Now substituting the values => 20 / 3 = 2 x 3.14 x squareroot of (L / 9.81) => 3.33 = 3.14 x squareroot of (L / 9.81) => squareroot of (L / 9.81) = 3.33 / 3.14 => L / 9.81 = 1.06^2 => L = 1.13 x 9.81 Length of the pendulum = 11 m

Sublimation- which change of state is shown in model