A95 kg clock initially at rest on a horizontal floor requires a 650 n horizontal force to set it in motion. after the clock is in motion, a horizontal force of 560 n keeps it moving with a constant velocity. a) what is the μs between the clock and the floor? .70b) what is the μk between the clock and the floor?

Explanation:

Mass of the clock, m = 95 kg

The horizontal force acting on the clock to set it in motion,

A horizontal force to keep it moving is, F' = 560 N

Let is the coefficient of static friction. The horizontal force acting on the clock to set it in motion is given by :

Let is the coefficient of static friction. The force due to motion of the clock is given by :

Hence, this is the required solution.