Aflatbed truck is carrying a heavy crate. the coefficient of static friction between the crate and the bed of the truck is 0.75. what is the maximum rate at which the driver can decelerate and still avoid having the crate slide against the cab of the truck? g

We don't want the crate to slip, we are essential to see when the force of deceleration is equal to the force of friction.

Let:

m = mass of the crate 

a = acceleration (in this case deceleration of the truck) 

g = acceleration due to gravity, 9.8 m/s^2 

μ = coefficient of friction, 0.73 

Then 

ma = μmg 

a = μg 

a = 0.75 * 9.8 m/s^2 

a = 7.35 m/s^2 

Therefore, the driver can securely decelerate at about 7.2 m/s^2, any tougher and the crate will probably slide in contradiction of the cab.

powerful computers now, not then

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.