A48.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. the flux in this position is measured to be 5.18 105 n · m2/c. what is the magnitude of the electric field?

At the point of maximum flux, the electric field is directed normal to the plane of the circular loop. The electric flux may be calculated as, Φ = E * A Where we assume that the electric field, E, is uniform over the area of the circle, A. We may solve for an unknown electric field magnitude as, E = Φ / A Where we are told that the flux is: Φ = 5.18 E5 N m^2 / C, and we can calculate the area of the loop as, A = pi * (D/2)^2 = (3.1415) * (0.48 m / 2)^2 = .1809504 m^2 Therefore, E = (5.18 E5 N m^2 / C) / (.1809504 m^2) E = ~2.86 E6 N/C

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