Afrog jumps with a velocity of 3.2 m/s at an angle of 25 degrees above horizontal. what is the vertical component of its velocity?

1.35m/s

Explanation:

This is done by locating the position or velocity of the frog in space and resolving the force.

Since the velocity 3.2m/s is at 25° above the horizontal, the vertical component of the velocity can be gotten by resolving the force to the positive y axis to give Vy = V sin(theta)

Given V = 3.2m/s

theta = 25°

Vy = 3.2sin25° (since the angle is at 25°above the horizontal I.e in the positive plane

Vy = 1.35m/s

it may be wrong but i think its a

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