An 8.0 kilogram cart moving to the right at 4.0 meters per second about to make a head-on collision with a 4.0 kilogram cart moving to the left at 6.0 per second. after the collision, the 4.0 kilogram cart moves to the right at 3.0 meters per second. what is the velocity of the 8.0 kilogram cart after the collision?

This question involves the concept of the law of conservation of momentum.

The velocity of the 8 kg cart after the collision is "4 m/s left direction".

According to the law of conservation of momentum, the total momentum of an isolated system before and after the collision remains constant.

where,

Taking the right side as the positive direction and the left side as the negative direction.

Therefore,

v₁ = - 4 m/s

negative sign shows left direction.

Learn more about the law of conservation of momentum here:

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when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

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