Aspaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. what distance has the spaceship covered after 12.0 seconds? 6.96 × 102 meters 1.27 × 103 meters 5.70 × 102 meters 1.26 × 102 meters 6.28 × 102 meters

Distance,

Explanation:

Given that,

Initial velocity of the spaceship, u = 58 m/s

Final speed of the spaceship, v = 153 m/s

Time, t = 12 s

We need to find the distance covered by the spaceship after 12 seconds. Let it is equal to s. Using first equation of motion as :

Now use third equation of motion as :

s = 1267.06 meters

or

So, the distance covered by the spaceship is . Hence, this is the required solution.

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