During a baseball game, a batter hits a high pop-up. if the ball remains in the air for 6.0 s, how high does it rise? hint: calculate the height using the second half of the trajectory.

The maximum height reached by the baseball is 44.1 m

The given parameter:

time for the entire motion of the baseball = time spent in air, T = 6.0 s

time to reach the maximum height,

To find:

The maximum height reached by the baseball using second half of the trajectory is calculated as;

where;

u is the initial velocity = 0

Thus, the maximum height reached by the baseball is 44.1 m

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therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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