Two metal balls have charges of 7.1 × 10-6  coulombs and  6.9 × 10-6  coulombs. they are 5.7 × 10-1  meters apart. what is the force of interaction between the two balls?   (k  = 9.0 × 109  newton·meters2/coulomb2) 5.7 newtons 6.9 newtons 7.1 newtons 1.4 newtons

Hey there, Your answer wold be 1.36 newtons rounded to 1.4 newton. This is how!

force = k (q1 * q2) / r^2 

= (9.0 × 10^9 Nm^2/C^2) [(7.1 × 10^-6 C) (6.9 × 10^-6 C)] / (5.7 × 10^-1 m)^2 

= [ 9.0 × 7.1 × 6.9 / (5.7)^2 ] × 10^-1 N 

= 13.6 × 10^-1 N 

= 1.36 N

ANSWER-1.4 

HOPE I HELPED

The answer is a i think