A330-kg piano slides 3.6 m down a 28 \incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. the coefficient of friction is 0.40. calculate the force exerted by the man

he role of "man" is to just stop it from getting accelerated let F be the force by man up along >. net force on block = m a (down) = mg sin 28 - F - uk(mg cos 28) since acceleration a = 0 mg sin 28 = F + uk(mg cos 28) F = mg[sin28 - 0.4 cos 28] = 376.1 N work done by man = F * d cos 180 = - F *3.6 = - 1353.96 J -ve sign because F and displacement are 180 deg apart ... work done by friction = - 0.4 {mg cos 28} * 3.6 = - 4111.85 J ... work done by gravity = + {mg sin 28} * 3.6 = 5465.78 J net work done = net force *3.6 = 0 *3.6 = 0 there is no net force on piano net work done = 5465.78 - 1353.96 - 4111.85 = 0 (very very close to zero) because decimal places??

Ifound this on google “the middle ear contains three tiny bones known as the ossicles: malleus, incus, and stapes. the ossicles were given their latin names for their distinctive shapes; they are also referred to as the hammer, anvil, and stirrup, respectively.” i hope this you for what your looking for

What formula  this one  (x_/