Acar is driving along a circular track of diameter d=.85km at a constant speed of v=28.5m/s. write an expression for the magnitude of the acceleration a of the car in terms of the given parameters

a = (2 v²)/d = 1.9 m/s²

Explanation:

In circular motion, the acceleration is given by:

a = v²/r = v²/(d/2) = (2 v²)/d

where v is the velocity and r is the radius of the circular path in which the vehicle is moving. d is the diameter of the circular path.

It is given that:

v = 28.5 m/s

r = d/2 = 0.85 km /2 = 0.425 km = 425 m

⇒ a = (28.5 m/s)²/425 m = 1.9 m/s²

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