Physics, 14.07.2019 20:50 blonk

A5 n force pushes on the right side of a box. at the same time, a 10 n force pushes on the left side of the box. what happens to the box?

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Answer from: littleprinces

The resultant force is 5N.So the box moves to right with constant acceleration.

Answer from: martinezalex829

The box will displace towards right side.

Explanation:

In the given problem, a 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. The net force acting on the force is 5 N.

The magnitude of the force acting on the box from the left side is more than the force acting on the box from the right side. The body will displace in that direction in which the magnitude of the applied force is more.

The box is displaced to right by a net force of 5 N.

Therefore, the box will displace towards right side.

Answer from: Quest

multiple allele inheritance is traits controlled by more than 2 alleles (ex: pigeons having 3 alleles of one gene govern their feather color).

With the physics questions above! only give correct answers. this is urgent by the way. for any !

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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A5 n force pushes on the right side of a box. at the same time, a 10 n force pushes on the left side...

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