Adaredevil decides to jump a canyon of width 8.88 m. to do so, he drives a motorcycle up an incline sloped at an angle of 22.5 ◦ . the acceleration of gravity is 9.8 m/s 2 . what minimum speed must he have in order to clear the canyon? answer in units of m/s.

What we need first is the formula to calculate maximum horizontal distance. It is: R = v^2(Sin 2A)/g where R is range, v is velocity, A is angle, and g is the gravity constant. we know that R=8.88 meters, A= 22.5 degrees, and g= 9.8 m/s^2 What we are looking for is v=?. We need to solve the equation for v. That gives us: v =((R*g)/(Sin(2* 22.5)))**1/2 Next, all we have to do is plugin the values. v = ((8.88m * 9.8 m/s**2)/(sin(2*22.5 degrees))**1/2 All this give us v = 10.11 m/s

Try c ? that’s what i got

If there was no gravity then their would be no downword force on the football to have it return the the grownd, and if there was no friction (mainly air friction) then there would be no opposing force the stop the ball from moving through the air allowing the ball to travle ∞.