A66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 170 m from top to bottom. at the bottom, the skier is moving 11 m/s.

I believe this question ask for the energy dissipated by friction.

The overall energy equation for this is:

F = PE – KE

where F is friction loss, PE is potential energy = m g h, KE is kinetic energy = 0.5 m v^2

F = 66 kg * 9.8 m/s^2 * 170 m – 0.5 * 66  kg * (11 m/s)^2

F = 105,963 J  ~  106,000 J 

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