Physics, 07.07.2019 12:50 death2833

Is the distance on a round-trip positive, negative, or zero?

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Answer from: naterjax

The distance of every object in a round trip is always positive

Distance is a scalar quantity, the total distance of an object in any trip is the total path covered by the object from the starting point to the finish point.

In a round trip, the object start's from one point and makes a circular movement, then returns to the same starting point. The total distance of the object is the equivalent to the circumference of the circle. This measurement will be a positive value.

On the other hand, the displacement of the object will be zero. Displacement is the change in the position of an object.

Thus, we can conclude that the distance of every object in a round trip is always positive while the displacement is zero.

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Answer from: fonsworth5

On a round trip, where you return to the place you started from, the distance for the whole trip is positive, and the displacement is zero.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

the part of the wave he is travelling on is the crest

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