Aball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. what is the average speed of the ball as it rolls the 10 meters? 1) 2.5m/s 2) 10m/s 3) 12.5m/s 4) 15m/s ( show calculation)

Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m

The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²

The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s

The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s

12.5 m/s